X^2-65x+980=0

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Solution for X^2-65x+980=0 equation: 



X^2-65X+980=0

a = 1; b = -65; c = +980;
Δ = b2-4ac
Δ = -652-4·1·980
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-\sqrt{305}}{2*1}=\frac{65-\sqrt{305}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+\sqrt{305}}{2*1}=\frac{65+\sqrt{305}}{2}
$

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